Import Question JSON

Current Question (ID: 8356)

Question:

$\text{The correct statement for a reversible process in a state of equilibrium is:}$

Options:

1. $\Delta G = -2.30RT \log K$
2. $\Delta G = 2.30RT \log K$
3. $\Delta G^o = -2.30RT \log K$
4. $\Delta G^o = 2.30RT \log K$

Solution:

$\text{Hint: } \Delta G \text{ is zero at equilibrium}$\n\n$\text{We know that,}$\n\n$\Delta G = \Delta G^o + 2.303 RT \log Q$\n\n$\text{At equilibrium, } \Delta G = 0 \text{ and } Q = K$\n\n$\text{then } \Delta G = \Delta G^o + 2.303 RT \log K = 0$\n\n$\text{Hence, } \Delta G^o = -2.303 RT \log K$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}