Import Question JSON

Current Question (ID: 8363)

Question:

$\text{In the reaction, } \Delta H \text{ and } \Delta S \text{ both are positive. The condition under which the reaction would not be spontaneous is -}$

Options:

1. $\Delta H > T\Delta S$
2. $\Delta S = \Delta H/T$
3. $\Delta H = T\Delta S$
4. $\text{All of the above}$

Solution:

$\text{Hint: } \Delta G = +\text{ve for non spontaneous reaction.}$\n\n$\text{The formula of Gibbs free energy is as follows:}$\n\n$\Delta G = \Delta H - T\Delta S$\n\n$\text{If both } \Delta H \text{ and } \Delta S \text{ are positive. Then in all conditions, that is, } \Delta H > T\Delta S\text{, } \Delta S = \Delta H/T\text{, and } \Delta H = T\Delta S \text{ reaction is not be spontaneous.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}