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Current Question (ID: 8367)

Question:

$\text{Match the following equilibria with the corresponding condition.}$ $\text{A. Liquid} \rightleftharpoons \text{Vapour}$ $\text{B. Solid} \rightleftharpoons \text{Liquid}$ $\text{C. Solid} \rightleftharpoons \text{Vapour}$ $\text{D. Solute (s)} \rightleftharpoons \text{Solute (solution)}$ $\text{1. Saturated solution}$ $\text{2. Boiling point}$ $\text{3. Sublimation point}$ $\text{4. Melting point}$ $\text{5. Unsaturated solution}$

Options:

1. $\text{A-2, B-4, C-3, D-1}$
2. $\text{A-1, B-2, C-3, D-5}$
3. $\text{A-5, B-4, C-3, D-2}$
4. $\text{A-4, B-5, C-3, D-2}$

Solution:

$\text{Hint: At the boiling point, the liquid phase is converted into the vapour phase.}$ $\text{Explanation:}$ $\text{A. Liquid} \rightleftharpoons \text{Vapour equilibrium exists at the boiling point.}$ $\text{B. Solid} \rightleftharpoons \text{Liquid equilibrium exists at the melting point.}$ $\text{C. Solid} \rightleftharpoons \text{Vapour equilibrium exists at the sublimation point.}$ $\text{D. Solute (s)} \rightleftharpoons \text{Solute (solution) equilibrium exists at a saturated solution.}$ $\text{Therefore, the correct matching is:}$ $\text{A-2 (Boiling point)}$ $\text{B-4 (Melting point)}$ $\text{C-3 (Sublimation point)}$ $\text{D-1 (Saturated solution)}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}