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Current Question (ID: 8371)

Question:

$\text{If the molar concentration of SnCl}_4 \text{ is } 1.5 \times 10^{-3} \text{ mol L}^{-1}\text{, the concentration of chloride ions will be:}$

Options:

1. $3.0 \times 10^{-3}$
2. $6.0 \times 10^{-3}$
3. $0.3 \times 10^{-3}$
4. $0.6 \times 10^{-6}$

Solution:

$\text{Hint: SnCl}_4 \rightleftharpoons \text{Sn}^{+4} + 4 \text{Cl}^-$ $\text{The reaction is as follows:}$ $\text{SnCl}_4 \rightleftharpoons \text{Sn}^{+4} + 4 \text{Cl}^-$ $1.5 \times 10^{-3} \text{ M solution of SnCl}_4 \text{ produces 4 times chloride ion as per the initial concentration. The calculation is shown below:}$ $\text{SnCl}_4 \rightleftharpoons \text{Sn}^{+4} + 4 \text{Cl}^-$ $1.5 \times 10^{-3} \quad\quad\quad 4 \times 1.5 \times 10^{-3} = 6 \times 10^{-3}$ $\text{Hence, the answer is option 2.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}