Import Question JSON

Current Question (ID: 8372)

Question:

$\text{Reaction quotient for the reaction, } \text{N}_2\text{(g)} + 3\text{H}_2\text{(g)} \rightleftharpoons 2\text{NH}_3\text{(g)} \text{ is given by}$ $Q = \frac{[\text{NH}_3]^2}{[\text{N}_2][\text{H}_2]^3}. \text{The reaction will proceed from right to left if } K_c \text{ value is:}$

Options:

1. $Q < K_c$
2. $Q = 0$
3. $Q > K_c$
4. $Q = K_c$

Solution:

$\text{Hint: If } Q > K_c, \text{ reaction will proceed in backward reaction.}$ $\text{Explanation:}$ $\text{As reaction quotient (Q) is the ratio of concentration of products to the concentration of reactants, therefore, for } Q > K_c, \text{ the reaction will proceed from right to left.}$ $\text{When } Q > K_c:\text{ The concentration of products is too high relative to reactants, so the reaction shifts backward (right to left) to reach equilibrium.}$ $\text{When } Q < K_c:\text{ The concentration of reactants is too high relative to products, so the reaction shifts forward (left to right).}$ $\text{When } Q = K_c:\text{ The reaction is at equilibrium, no net change occurs.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}