Import Question JSON

Current Question (ID: 8373)

Question:
$\text{An incorrect statement about equilibrium among the following is:}$
Options:
  • 1. $\text{Equilibrium is possible only in a closed system at a constant temperature.}$
  • 2. $\text{All measurable properties of the system remain constant.}$
  • 3. $\text{All the physical processes stop at equilibrium.}$
  • 4. $\text{The opposing processes occur at the same rate and there is a dynamic but stable condition.}$
Solution:
$\text{Hint: At equilibria, rate of forward and backward reaction is equal.}$ $\text{At the stage of equilibria involving physical processes like melting of ice and freezing of water etc., processes does not stop but the opposite processes i.e., forward and reverse process occur with the same rate.}$ $\text{According to the definition of equilibrium, the opposing processes occur at the same rate and there is a dynamic but stable condition. This means physical processes do not stop at equilibrium, rather they continue at equal rates in forward and reverse directions.}$ $\text{Option 1 is correct: Equilibrium is possible only in a closed system at a constant temperature.}$ $\text{Option 2 is correct: All measurable properties of the system remain constant.}$ $\text{Option 3 states that all physical processes stop at equilibrium, which contradicts the definition of dynamic equilibrium where processes continue but at equal rates.}$ $\text{Option 4 is correct: The opposing processes occur at the same rate and there is a dynamic but stable condition.}$ $\text{Therefore, the incorrect statement about equilibrium is option 3.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}