Import Question JSON

Current Question (ID: 8376)

Question:

$\text{Which of the following is an example of a reversible reaction?}$

Options:

1. $\text{KNO}_3\text{(aq)} + \text{NaCl}\text{(aq)} \rightleftharpoons \text{KCl}\text{(aq)} + \text{NaNO}_3\text{(aq)}$
2. $2\text{Na}\text{(s)} + \text{H}_2\text{O}\text{(l)} \rightleftharpoons 2\text{NaOH}\text{(aq)} + \text{H}_2\text{(g)}$
3. $\text{AgNO}_3\text{(aq)} + \text{NaCl}\text{(aq)} \rightleftharpoons \text{AgCl}\text{(s)} + \text{NaNO}_3\text{(aq)}$
4. $\text{Pb(NO}_3\text{)}_2\text{(aq)} + 2\text{NaI}\text{(aq)} \rightleftharpoons \text{PbI}_2\text{(s)} + 2\text{NaNO}_3\text{(aq)}$

Solution:

$\text{Hint: Ion exchange reactions are reversible}$ $\text{As all the reactants and products are present in an aqueous form in}$ $\text{KNO}_3\text{(aq)} + \text{NaCl}\text{(aq)} \rightleftharpoons \text{KCl}\text{(aq)} + \text{NaNO}_3\text{(aq)}$ $\text{So it is a reversible ion-exchange reaction. In other reactions given in the question, either solid or gas is generated which is insoluble or volatile and hence makes the reaction unidirectional.}$ $\text{Analysis of other options:}$ $\text{Option 2: Produces H}_2 \text{ gas which escapes, making it irreversible}$ $\text{Option 3: Forms AgCl solid precipitate which is insoluble, making it irreversible}$ $\text{Option 4: Forms PbI}_2 \text{ solid precipitate which is insoluble, making it irreversible}$ $\text{Therefore, only option 1 represents a truly reversible reaction where all species remain in solution.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}