Import Question JSON

Current Question (ID: 8381)

Question:
$\text{Given an endothermic reaction:}$ $\text{CH}_4\text{(g)} + \text{H}_2\text{O}\text{(g)} \rightleftharpoons \text{CO}\text{(g)} + 3\text{H}_2\text{(g)}$ $\text{If the temperature is increased, then:}$
Options:
  • 1. $\text{The equilibrium will not be disturbed.}$
  • 2. $\text{The equilibrium will shift in the backward direction.}$
  • 3. $\text{The equilibrium will shift in the forward direction.}$
  • 4. $\text{None of the above.}$
Solution:
$\text{Hint: Use Le-Chatelier's Principle}$ $\text{Explanation:}$ $\text{According to Le Chatelier's principle, as the reaction is endothermic, the equilibrium will shift in the forward direction if the temperature is increased. Hence, option third is the correct answer.}$ $\text{Le Chatelier's Principle states that when a system at equilibrium is subjected to a change in conditions, the equilibrium will shift to counteract that change.}$ $\text{For endothermic reactions:}$ $\text{• Heat is absorbed during the forward reaction}$ $\text{• We can think of heat as a reactant: Heat + Reactants} \rightleftharpoons \text{Products}$ $\text{• When temperature increases, we are adding more "heat"}$ $\text{• The system responds by shifting forward to consume the added heat}$ $\text{• This favors the formation of more products}$ $\text{Therefore, increasing temperature in an endothermic reaction shifts the equilibrium toward the products (forward direction).}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}