Import Question JSON

Current Question (ID: 8383)

Question:

$\text{Mark the conditions that favour the maximum product formation in the given reaction.}$ $\text{A}_2\text{(g)} + \text{B}_2\text{(g)} \rightleftharpoons \text{X}_2\text{(g)}, \Delta_r H = -X \text{ kJ}$

Options:

1. $\text{Low temperature and High pressure}$
2. $\text{Low temperature and Low pressure}$
3. $\text{High temperature and High pressure}$
4. $\text{High temperature and Low pressure}$

Solution:

$\text{According to Le-Chatelier's principal}$ $\text{Exothermic reaction when } \Delta_r H < 0$ $\text{Then favorable conditions are low temperature and high pressure.}$ $\text{Detailed Analysis:}$ $\text{Temperature Effect:}$ $\text{Since } \Delta_r H = -X \text{ kJ (negative), this is an exothermic reaction.}$ $\text{For exothermic reactions, decreasing temperature favors the forward reaction.}$ $\text{Therefore, LOW TEMPERATURE is favorable.}$ $\text{Pressure Effect:}$ $\text{Reactants: A}_2\text{(g)} + \text{B}_2\text{(g)} = 2 \text{ moles of gas}$ $\text{Products: X}_2\text{(g)} = 1 \text{ mole of gas}$ $\text{Since the number of moles decreases (2 → 1), increasing pressure favors the forward reaction.}$ $\text{Therefore, HIGH PRESSURE is favorable.}$ $\text{Conclusion: Low temperature and high pressure favor maximum product formation.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}