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Question:
$\text{For the reaction,}$
$\text{PCl}_5\text{(g)} \rightleftharpoons \text{PCl}_3\text{(g)} + \text{Cl}_2\text{(g)}$
$\text{The forward reaction at constant temperature is favoured by:}$
Options:
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1. $\text{Introducing an inert gas at a constant volume}$
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2. $\text{Introducing chlorine gas at a constant volume}$
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3. $\text{Introducing an inert gas at constant pressure}$
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4. $\text{None of the above}$
Solution:
$\text{Hint: Follow Le Chatelier's principle}$
$\text{PCl}_5\text{(g)} \rightleftharpoons \text{PCl}_3\text{(g)} + \text{Cl}_2\text{(g)}$
$\text{Equilibrium moles: (a-x) \quad x \quad x}$
$\text{The addition of inert gas at constant V has no effect on reactions having } \Delta n = 0 \text{ or } \Delta n \neq 0. \text{ But the addition of inert gas at constant P has an effect on reactions having } \Delta n \neq 0, \text{ and no effect if } \Delta n = 0. \text{ The given reaction has } \Delta n \neq 0 \text{ and thus, only choice (c) is correct.}$
$\text{Analysis of each option:}$
$\text{Option 1: Inert gas at constant volume}$
$\text{• No effect on equilibrium because partial pressures remain unchanged}$
$\text{• Total pressure increases but individual concentrations stay the same}$
$\text{Option 2: Adding Cl}_2 \text{ at constant volume}$
$\text{• Increases [Cl}_2\text{] → shifts equilibrium backward (Le Chatelier's principle)}$
$\text{• Does not favor forward reaction}$
$\text{Option 3: Inert gas at constant pressure}$
$\text{• Volume must increase to maintain constant pressure}$
$\text{• Effectively decreases pressure of reacting gases}$
$\text{• For } \Delta n > 0 \text{ (1 → 2 moles), lower pressure favors forward reaction}$
$\text{• This favors the forward reaction}$
$\text{Therefore, introducing an inert gas at constant pressure favors the forward reaction.}$
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