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Current Question (ID: 8388)

Question:
$\text{Inert gas is added to the equilibrium PCl}_5\text{(g)} \rightleftharpoons \text{PCl}_3\text{(g) + Cl}_2\text{(g) at constant pressure. The degree of dissociation will:}$
Options:
  • 1. $\text{Remain unchanged}$
  • 2. $\text{Decrease}$
  • 3. $\text{Increase}$
  • 4. $\text{Decrease or increase but cannot be predicted with certainty}$
Solution:
$\text{Hint: Follow Le Chatelier's principle}$ $\text{Let's analyze what happens when an inert gas is added to the equilibrium at constant pressure:}$ $\text{PCl}_5\text{(g)} \rightleftharpoons \text{PCl}_3\text{(g) + Cl}_2\text{(g)}$ $\text{1. When an inert gas is added at constant pressure, the total volume of the system must increase to maintain the same pressure.}$ $\text{2. This increase in volume causes the concentration (moles per unit volume) of all reactants and products to decrease.}$ $\text{3. According to Le Chatelier's principle, the equilibrium will shift in the direction that counteracts this change.}$ $\text{4. The system will favor the side with a greater number of moles of gas to counteract the decrease in concentration.}$ $\text{In this reaction:}$ $\text{Left side: 1 mole of gas (PCl}_5\text{)}$ $\text{Right side: 2 moles of gas (PCl}_3 \text{ and Cl}_2\text{)}$ $\text{Since there are more moles of gas on the right side (products), the equilibrium will shift toward the products to counteract the decrease in concentration.}$ $\text{When the equilibrium shifts toward the products, the degree of dissociation of PCl}_5 \text{ increases.}$ $\text{Therefore, the degree of dissociation will increase when an inert gas is added at constant pressure.}$ $\text{The correct answer is option 3: Increase.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}