Import Question JSON

Current Question (ID: 8389)

Question:

$\text{According to Le-Chatelier's principle, adding heat to a solid} \rightleftharpoons \text{liquid equilibrium will cause the:}$

Options:

1. $\text{Temperature to increase}$
2. $\text{Temperature to decrease}$
3. $\text{Amount of liquid to decrease}$
4. $\text{Amount of solid to decrease}$

Solution:

$\text{Hint: The reaction goes in forward direction.}$ $\text{Explanation:}$ $\text{When we add heat to the equilibrium between solid and liquid state, then the equilibrium shifts towards liquid side and hence, the amount of solid decreases and the amount of liquid increases. The heat does not affect the temperature of the reaction.}$ $\text{Detailed Analysis:}$ $\text{The equilibrium can be written as:}$ $\text{Solid} + \text{Heat} \rightleftharpoons \text{Liquid}$ $\text{This is the melting process, which is endothermic (requires heat input).}$ $\text{According to Le Chatelier's Principle:}$ $\text{• When heat is added to the system, the equilibrium shifts to consume the added heat}$ $\text{• The system shifts in the direction that absorbs heat (forward direction)}$ $\text{• More solid converts to liquid}$ $\text{Result of adding heat:}$ $\text{• Amount of solid decreases (converts to liquid)}$ $\text{• Amount of liquid increases}$ $\text{• Temperature remains constant at the melting point during phase transition}$ $\text{Important Note: During a phase transition at equilibrium, the temperature remains constant until all of one phase is converted. The added heat energy goes into breaking intermolecular forces rather than increasing temperature.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}