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Current Question (ID: 8390)

Question:
$\text{On increasing the pressure, the direction in which the gas phase reaction proceeds to re-establish equilibrium is predicted by applying Le-Chatelier's principle. Consider the reaction,}$ $\text{N}_2\text{(g)} + \text{3H}_2\text{(g)} \rightleftharpoons \text{2NH}_3\text{(g)}$ $\text{Which of the following is correct, if the total pressure at which the equilibrium is established is increased without changing the temperature?}$
Options:
  • 1. $\text{K will remain the same.}$
  • 2. $\text{K will decrease.}$
  • 3. $\text{K will increase.}$
  • 4. $\text{K will increase initially and then decrease, when pressure is very high.}$
Solution:
$\text{Hint: K is only temperature dependent.}$ $\text{Explanation:}$ $\text{Let's analyze this question carefully:}$ $\text{1. The equilibrium constant K for a reaction is a function of temperature only. It does not change with pressure, concentration, or the addition of a catalyst.}$ $\text{2. While pressure changes can shift the position of equilibrium (i.e., the relative amounts of reactants and products), they do not change the value of the equilibrium constant K itself.}$ $\text{3. When pressure increases, according to Le Chatelier's principle, the reaction will shift to favor the side with fewer moles of gas:}$ $\text{N}_2\text{(g)} + \text{3H}_2\text{(g)} \rightleftharpoons \text{2NH}_3\text{(g)}$ $\text{Left side: 4 moles of gas (1 mole of N}_2 \text{ and 3 moles of H}_2\text{)}$ $\text{Right side: 2 moles of gas (2 moles of NH}_3\text{)}$ $\text{So increasing pressure will shift the equilibrium toward the right (product side) because there are fewer moles of gas on that side. This will increase the concentration of NH}_3 \text{ and decrease the concentrations of N}_2 \text{ and H}_2\text{.}$ $\text{4. However, this shift in equilibrium does not change the value of K. The equilibrium constant K depends only on temperature.}$ $\text{Therefore, even though increasing pressure will shift the position of this equilibrium toward the products (right side), the value of the equilibrium constant K will remain the same as long as the temperature is constant.}$ $\text{The correct answer is option 1: K will remain the same.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}