Import Question JSON

Current Question (ID: 8408)

Question:

$\text{Hint: At equilibrium } K_c = Q_c.$ $\text{At equilibrium, the value of } K_c \text{ and } Q_c \text{ is the same. When } K_c > Q_c, \text{ the reaction mainly goes in the forward direction and when } K_c < Q_c, \text{ the reaction mainly goes in the backward direction.}$

Options:

1. Both assertion & reason are true and the reason is the correct explanation of the assertion.
2. Both assertion & reason are true but the reason is not the correct explanation of the assertion.
3. $\text{Assertion is a true statement but the reason is false.}$
4. $\text{Both assertion and reason are false statements.}$

Solution:

$\text{Analysis of the assertion and reason:}$ $\text{Assertion: At equilibrium, } K = Q_c \text{ - This is TRUE. At equilibrium, the reaction quotient } Q_c \text{ equals the equilibrium constant } K_c.$ $\text{Reason: When } K_c > Q_c, \text{ the reaction mainly goes in the forward direction - This is also TRUE. When the equilibrium constant is greater than the reaction quotient, the reaction proceeds forward to reach equilibrium.}$ $\text{However, the reason does not directly explain the assertion. The assertion states what happens AT equilibrium, while the reason describes what happens BEFORE equilibrium is reached.}$ $\text{Therefore, both statements are true, but the reason is not the correct explanation of the assertion.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}