Import Question JSON

Current Question (ID: 8413)

Question:

\text{Assertion: The equilibrium constant of a reaction changes by changing the stoichiometric coefficients of the reaction.} \text{Reason: The reaction, } 2\text{NO}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g) \text{ and } \text{NO}_2(g) \rightleftharpoons \frac{1}{2}\text{N}_2\text{O}_4(g) \text{ have the same equilibrium constant.}

Options:

1. $\text{Both assertion & reason are true and the reason is the correct explanation of the assertion.}$
2. $\text{Both assertion & reason are true but the reason is not the correct explanation of the assertion.}$
3. $\text{Assertion is a true statement but the reason is false.}$
4. $\text{Both assertion and reason are false statements.}$

Solution:

$\text{Hint: The equilibrium constant of a reaction changes by changing the stoichiometric coefficients of the reaction.}$ $\text{Explanation:}$ $\text{Change the stoichiometric coefficients in a chemical equation by multiplying throughout by a factor then we must make sure that the expression for equilibrium constant also reflects that change. The equilibrium constant of a reaction changes by changing the stoichiometric coefficients of the reaction.}$ $\text{The reaction is as follows:}$ $2\text{NO}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g) \quad K$ $\text{NO}_2(g) \rightleftharpoons \frac{1}{2}\text{N}_2\text{O}_4(g) \quad K' = (K)^{1/2}$ $\text{Hence, Assertion is a true statement but Reason is false.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}