Import Question JSON

Current Question (ID: 8414)

Question:
\text{One mole of H}_2\text{O and one mole of CO are taken in a 10 L vessel and heated to 725 K.} \text{At equilibrium, 40\% of water (by mass) reacts with CO according to the equation:} \text{H}_2\text{O(g) + CO(g) } \rightleftharpoons \text{ H}_2\text{(g) + CO}_2\text{(g)} \text{The equilibrium constant for the above-mentioned reaction would be:}
Options:
  • 1. $0.66$
  • 2. $0.35$
  • 3. $0.44$
  • 4. $0.82$
Solution:
\text{Hint: } K_c = \frac{[H_2][CO_2]}{[H_2O][CO]} \text{Step 1: Find equilibrium concentrations} \text{Reaction: } H_2O_{(g)} + CO_{(g)} \rightleftharpoons H_{2(g)} + CO_{2(g)} \text{Initial: } 0.1M \text{ each for reactants, } 0M \text{ for products} \text{At equilibrium: } 0.06M \text{ for reactants, } 0.04M \text{ for products} \text{Step 2: Calculate } K_c K_c = \frac{0.04 \times 0.04}{0.06 \times 0.06} = 0.44

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}