Import Question JSON

Current Question (ID: 8416)

Question:
\text{Match the standard free energy of the reaction with the corresponding equilibrium constant.} \text{A. } \Delta G^{\circ} > 0 \text{ 1. } K > 1 \text{B. } \Delta G^{\circ} < 0 \text{ 2. } K = 1 \text{C. } \Delta G^{\circ} = 0 \text{ 3. } K = 0 \text{ 4. } K < 1 \text{Codes:}
Options:
  • 1. $\text{A-4, B-1, C-2}$
  • 2. $\text{A-1, B-2, C-3}$
  • 3. $\text{A-2, B-4, C-3}$
  • 4. $\text{A-4, B-1, C-3}$
Solution:
$\text{Hint: } \Delta G^{\circ} = -RT \ln K$ $\text{As we know that, } \Delta G^{\circ} = -RT \ln K$ $\text{A. If } \Delta G^{\circ} > 0 \text{ i.e., } \Delta G^{\circ} \text{ is positive, then } \ln K \text{ is negative i.e., } K < 1$ $\text{B. If } \Delta G^{\circ} < 0 \text{ i.e., } \Delta G^{\circ} \text{ is negative then } \ln K \text{ is positive i.e., } K > 1$ $\text{C. If } \Delta G^{\circ} = 0, \text{ then } \ln K = 0 \text{ i.e., } K = 1$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}