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Current Question (ID: 8422)

Question:

\text{The dissociation of solid NH}_4\text{SH in a closed container produces a pressure of 4 atm at 95}^\circ\text{C, then } K_p \text{ for the reaction will be:} \text{NH}_4\text{SH}_{(\text{s})} \rightleftharpoons \text{NH}_3\text{(g)} + \text{H}_2\text{S}_{(\text{g})}

Options:

1. $4$
2. $8$
3. $16$
4. $5$

Solution:

\text{Hint: } K_p = [P_{\text{NH}_3}][P_{\text{H}_2\text{S}}] \text{Step 1:} \text{The reaction is as follows: } \text{NH}_4\text{SH} \rightleftharpoons \text{NH}_3\text{(g)} + \text{H}_2\text{S}\text{(g)} \text{As per the reaction, NH}_3 \text{ and H}_2\text{S} \text{ moles are equal at equilibrium} \text{Let mole of NH}_3 \text{ and H}_2\text{S} \text{ is } x \text{ respectively} \text{Partial pressure of NH}_3 = P_T \times X_{\text{NH}_3} = 4 \times \frac{x}{x+x} = 4 \times \frac{1}{2} = 2 \text{ atm} \text{Same for H}_2\text{S}\text{(g)} \text{Partial pressure of H}_2\text{S} = 2 \text{ atm} \text{Step 2:} \text{Calculate the value of } K_p \text{ as follows:} K_p = P_{\text{NH}_3} \times P_{\text{H}_2\text{S}} = 2 \times 2 = 4 \text{Hence option 1 is correct}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}