Import Question JSON

Current Question (ID: 8463)

Question:

$\text{When equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed, the pH of the resulting solution will be:}$

Options:

1. 12.65
2. 2.0
3. 7.0
4. 1.04

Solution:

$\text{Hint: } M_v = \frac{M_1V_1 - M_2V_2}{V_1 + V_2}$ $\text{Step 1:}$ $M_v = \frac{M_1V_1 - M_2V_2}{V_1 + V_2}$ $= \frac{0.1 \times 1 - 0.01 \times 1}{2}$ $= \frac{0.09}{2} = 0.045 \text{ M}$ $\text{Step 2:}$ $\text{pOH} = -\log(0.045) \approx 1.3$ $\text{pH} = 14 - 1.3$ $= 12.6$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}