Import Question JSON

Current Question (ID: 8465)

Question:

$\text{The ionic product of water at 310 K is } 2.7 \times 10^{-14}\text{.}$ $\text{The pH of neutral water at this temperature will be:}$

Options:

1. $2.56$
2. $6.78$
3. $7.32$
4. $11.41$

Solution:

$\text{Hint: Ionic product of water} = [\text{H}^+][\text{OH}^-]$ $\text{STEP 1: Let } [\text{H}^+] = x$ $\text{Since } [\text{H}^+] = [\text{OH}^-]\text{; } K_w = x^2$ $\text{Given; } K_w \text{ at 310 K} = 2.7 \times 10^{-14}$ $\Rightarrow x^2 = 2.7 \times 10^{-14}$ $\Rightarrow x = 1.64 \times 10^{-7}$ $\text{STEP 2: Calculate pH}$ $[\text{H}^+] = 1.64 \times 10^{-7}$ $\text{Thus, pH} = -\log[\text{H}^+] = -\log(1.64 \times 10^{-7})$ $\Rightarrow \text{pH} = 6.78$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}