Import Question JSON

Current Question (ID: 8468)

Question:

$\text{Given below are two statements:}$ $\text{Assertion (A): An aqueous solution of ammonium carbonate is basic.}$ $\text{Reason (R): The acidic or basic nature of a salt solution of a salt of a weak acid and a weak base depends on the Ka and Kb values of the acid and the base forming it.}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{(A) is False but (R) is True.}$

Solution:

$\text{Hint: } K_b \text{ of } \text{NH}_4\text{OH} > K_a \text{ of } \text{H}_2\text{CO}_3$ $\text{The reaction is as follows:}$ $(\text{NH}_4)_2\text{CO}_3 \longrightarrow 2\text{NH}_4^+ + \text{CO}_3^{2-}$ $2\text{H}_2\text{O} \longrightarrow 2\text{OH}^- + 2\text{H}^+$ $\text{NH}_4\text{OH} \text{ (Weak base)} \quad \text{H}_2\text{CO}_3 \text{ (Weak acid)}$ $\text{If } K_b \text{ of } \text{NH}_4\text{OH} > K_a \text{ of } \text{H}_2\text{CO}_3$ $\text{The solution is basic.}$ $\text{or, If } K_a \text{ of } \text{H}_2\text{CO}_3 > K_b \text{ of } \text{NH}_4\text{OH}\text{; the solution is acidic. Hence, both assertion and reason are true and the reason is the correct explanation of assertion.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}