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Current Question (ID: 8470)

Question:
$\text{The solution that has the lowest pH is:}$ $\text{(assuming 100\% dissociation)}$
Options:
  • 1. $0.003 \text{ M HCl}$
  • 2. $0.005 \text{ M NaOH}$
  • 3. $0.002 \text{ M HBr}$
  • 4. $0.002 \text{ M KOH}$
Solution:
$\textbf{Hint: } \text{pH} = -\log[\text{H}^+]$ $\textbf{Explanation:}$ $\begin{array}{|c|c|c|c|} \hline 0.003\text{M HCl} & [\text{H}^+] = 0.003\text{M} & \text{pH} = -\log(0.003) & \text{pH} = 2.52 \\ \hline 0.005\text{M NaOH} & [\text{OH}^-] = 0.005\text{M} & \text{pOH} = -\log(0.005) & \text{pOH} = 2.30; \text{pH} = 11.70 \\ \hline 0.002\text{M HBr} & [\text{H}^+] = 0.002\text{M} & \text{pH} = -\log(0.002) & \text{pH} = 2.69 \\ \hline 0.002\text{M KOH} & [\text{OH}^-] = 0.002 & \text{pOH} = -\log(0.002) & \text{pOH} = 2.69; \text{pH} = 11.31 \\ \hline \end{array}$ $\text{So, } 0.003\text{M HCl} \text{ solution will have lowest pH among the following solutions.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}