Import Question JSON

Current Question (ID: 8471)

Question:

$\text{When 1 mL of 13.6 M HCl is diluted with water to give 1 litre of solution, the pH of the resultant solution will be:}$

Options:

1. $11.87$
2. $3.46$
3. $1.87$
4. $12.23$

Solution:

$\text{Hint: pH} = -\log[\text{H}^+]$ $\text{Explanation:}$ $\text{Step 1: Find [H}^+\text{]}$ $\text{For 1 mL of 13.6 M HCl diluted with water to give 1 L of the solution:}$ $13.6 \times 1 \text{ mL} = \text{M}_2 \times 1000 \text{ mL}$ $\text{Molarity of HCl solution; M}_2 = 1.36 \times 10^{-2} \text{ M} = [\text{H}^+]$ $\text{Step 2: Calculate pH of the solution is}$ $\text{We know that, pH} = -\log[\text{H}^+]$ $\text{pH} = -\log(1.36 \times 10^{-2}) = 1.87$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}