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Current Question (ID: 8485)

Question:
$\text{The pH of a 0.1 M solution of cyanic acid (HCNO) is 2.34. The ionization constant of the acid will be:}$
Options:
  • 1. $2.02 \times 10^{4}$
  • 2. $3.14 \times 10^{3}$
  • 3. $2.02 \times 10^{-4}$
  • 4. $1.01 \times 10^{-4}$
Solution:
$\text{Hint: Use }K_a = c \alpha^2$ $\text{Explanation:}$ $\text{Step 1: Calculate }[\text{H}^+]$ $\text{Given, Concentration(c) = 0.1M and pH = 2.34}$ $\text{pH} = -\log[\text{H}^+]$ $2.34 = -\log[\text{H}^+]$ $[\text{H}^+] = 4.5 \times 10^{-3}$ $\text{Step 2: Calculate degree of ionization}$ $\text{We know that, }[\text{H}^+] = c\alpha$ $4.5 \times 10^{-3} = 0.1 \times \alpha$ $\Rightarrow \alpha = 0.045$ $\text{Step 3: Calculate ionization constant}$ $K_a = c \alpha^2$ $\Rightarrow K_a = 0.1 \times (0.045)^2 \Rightarrow K_a = 2.02 \times 10^{-4}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}