Import Question JSON

Current Question (ID: 8491)

Question:
$\text{Which of the following is an amphiprotic (can accept and give protons) ion?}$
Options:
  • 1. $\text{HPO}_3^-$
  • 2. $\text{H}_2\text{PO}_2^-$
  • 3. $\text{H}_3\text{PO}_4$
  • 4. $\text{H}_2\text{PO}_4^-$
Solution:
$\text{Hint: Accept and give up a proton.}$ $\text{An amphiprotic substance can both donate or accept a proton.}$ $\text{HPO}_3^- \text{ is a conjugate base of } \text{H}_2\text{PO}_3\text{. It has only one acidic hydrogen. Thus, } \text{HPO}_3^- \text{ can only act as a base, not an acid.}$ $\text{H}_2\text{PO}_2^- \text{ is a conjugate base of } \text{H}_3\text{PO}_2\text{. It has only one acidic hydrogen. Thus, } \text{H}_2\text{PO}_2^- \text{ can only act as a base, not an acid.}$ $\text{H}_3\text{PO}_4 \text{ is an acid not a base.}$ $\text{Only } \text{H}_2\text{PO}_4^- \text{ is an amphiprotic substance because it can act as an acid as well as a base also.}$ $\text{H}_2\text{PO}_4^- \text{ can act as base and form } \text{H}_3\text{PO}_4\text{. It can act as an acid and form } \text{HPO}_4^{2-}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}