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Current Question (ID: 8508)

Question:
$\text{The mixture that can act like a buffer is:}$
Options:
  • 1. $\text{CH}_3\text{COOH} + \text{CH}_3\text{COONa}$
  • 2. $\text{NH}_4\text{NO}_3 + \text{NH}_4\text{OH}$
  • 3. $\text{50 ml 0.1 m NaCN} + \text{30 ml 0.1 m HCl}$
  • 4. $\text{All of the above}$
Solution:
$\text{Hint: Weak base or weak acid along with its salt form a buffer solution.}$ $\text{When 50 ml 0.1 m NaCN + 30 ml 0.1 m HCl then buffer solution is obtained. The reaction is as follows:}$ $\text{NaCN} + \text{HCl} \rightarrow \text{HCN} + \text{NaCl}$ $\text{millimole calculation:}$ $\text{NaCN: } 0.1 \times 50 = 5 \text{ millimoles}$ $\text{HCl: } 0.1 \times 30 = 3 \text{ millimoles}$ $\text{After reaction: 2 millimoles of NaCN remain, 3 millimoles of HCN are formed}$ $\text{After the reaction 2 millimole of NaCN and 3 millimole of HCN are present. Hence, it acts as a buffer solution.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}