Import Question JSON

Current Question (ID: 8523)

Question:
\text{Assertion (A): The aqueous solution of } \text{CH}_3\text{COONa is alkaline in nature.} \text{Reason (R): Sodium acetate undergoes anionic hydrolysis.}
Options:
  • 1. $\text{Both (A) and (R) are true and (R) is the correct explanation of (A).}$
  • 2. $\text{Both (A) and (R) are true but (R) is not the correct explanation of (A).}$
  • 3. $\text{(A) is true but (R) is false.}$
  • 4. $\text{Both (A) and (R) are false.}$
Solution:
\text{Hint: Acetic acid is a weak acid.} \text{Explanation:} \text{The aqueous solution of } \text{CH}_3\text{COONa} \text{ is alkaline in nature. Because } \text{CH}_3\text{COONa} \text{ dissociates and forms } \text{CH}_3\text{COO}^- \text{ and } \text{Na}^+\text{. The anion undergoes anionic hydrolysis by reacting with water. The reaction is as follows:} \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \text{Due to the formation of hydroxide ions, pH increases and the aqueous solution of } \text{CH}_3\text{COONa} \text{ becomes alkaline in nature.} \text{Hence, Assertion is a true statement but Reason is false.}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}