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Current Question (ID: 8525)

Question:
$\text{The percentage degree of hydrolysis of a salt of weak acid (HA) and weak base (BOH) in its } 0.1 \text{ M solution is found to be } 10\%. \text{ If the molarity of the solution is } 0.05 \text{ M, the percentage hydrolysis of the salt should be -}$
Options:
  • 1. $5\%$
  • 2. $10\%$
  • 3. $20\%$
  • 4. $\text{None of the above}$
Solution:
$\text{Hint: Percentage of hydrolysis of the salt remain same.}\text{The degree of hydrolysis of a salt of weak acid and weak base is independent of the concentration of salt. So the percentage of hydrolysis of the salt is } 10\%.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}