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Current Question (ID: 8540)

Question:

$\text{The solubility product of silver chromate is } 1.1 \times 10^{-12}\text{. The solubility of silver chromate will be:}$

Options:

1. $6.5 \times 10^{-5} \text{ mol L}^{-1}$
2. $6.5 \times 10^{-6} \text{ mol L}^{-1}$
3. $5.5 \times 10^{-5} \text{ mol L}^{-1}$
4. $5.5 \times 10^{-6} \text{ mol L}^{-1}$

Solution:

$\text{Hint: Silver chromate is Ag}_2\text{CrO}_4$ $\text{The molecular formula of silver chromate is Ag}_2\text{CrO}_4\text{. The reaction is as follows:}$ $\text{Ag}_2\text{CrO}_4 \rightarrow 2\text{Ag}^+ + \text{CrO}_4^{2-}$ $\text{Calculate the solubility of silver chromate is as follows:}$ $K_{sp} = [\text{Ag}^+]^2[\text{CrO}_4^{2-}]$ $\text{Let solubility = S, then } [\text{Ag}^+] = 2\text{S} \text{ and } [\text{CrO}_4^{2-}] = \text{S}$ $K_{sp} = [2\text{S}]^2[\text{S}] = 4\text{S}^3$ $\frac{1.1 \times 10^{-12}}{4} = \text{S}^3$ $\text{S} = \left(\frac{1.1 \times 10^{-12}}{4}\right)^{1/3}$ $\text{S} = 6.5 \times 10^{-5} \text{ mol L}^{-1}$ $\text{The solubility of silver chromate is } 6.5 \times 10^{-5} \text{ mol L}^{-1}\text{.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}