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Current Question (ID: 8547)

Question:
$\text{In which of the following will the solubility of } \text{AgCl be the minimum?}$
Options:
  • 1. $\text{0.1 M } \text{NaNO}_3$
  • 2. $\text{Water}$
  • 3. $\text{0.1 M } \text{NaCl}$
  • 4. $\text{0.1 M } \text{NaBr}$
Solution:
\text{Hint: Common ion effect} \text{When AgCl is added to 0.1 M NaCl solution then solubility of AgCl decreases as compared to other options, that is, 0.1 M } \text{NaNO}_3\text{, water and 0.1 M NaBr. The decrease in solubility of AgCl is due to common ion effect by } \text{Cl}^{-} \text{ ion.} \text{The reaction is as follows:} \text{AgCl } \rightleftharpoons \text{ Ag}^{+} + \text{Cl}^{-} \text{The concentration of } \text{Cl}^{-} \text{ in the product side increases when AgCl is added to 0.1 M NaCl solution. Hence, backward reaction is favoured. Thus, the correct answer is 0.1 M NaCl.}

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}