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Current Question (ID: 8567)

Question:

$\text{The formulas for the following compounds are:}$ $(\text{a}) \text{ Mercury(II) chloride and } (\text{b}) \text{ Thallium(I) sulphate}$

Options:

1. $\text{HgCl}_2, \text{Tl}_2\text{SO}_4$
2. $\text{Hg}_2\text{Cl}_2, \text{Tl}_2\text{SO}_4$
3. $\text{HgCl}_2, \text{TlSO}_4$
4. $\text{HgCl}_2, \text{Tl}_3\text{SO}_4$

Solution:

$\text{HINT: Molecule should be neutral.}$ $\text{Explanation:}$ $(\text{a}) \text{ Mercury (II) chloride: Cl has -1 charge so, for Hg(II) there should be two Cl}^- \text{ ions.}$ $\text{HgCl}_2$ $(\text{b}) \text{ Thallium (I) sulphate: Sulphate has -2 charge thus, for Tl(I) there should be two Tl and one SO}_4^{2-}$ $\text{Tl}_2\text{SO}_4$ $\text{Detailed Analysis:}$ $\text{For Mercury(II) chloride:}$ $\text{Mercury(II) means Hg}^{2+} \text{ (oxidation state +2)}$ $\text{Chloride is Cl}^- \text{ (charge -1)}$ $\text{To balance charges: Hg}^{2+} + 2\text{Cl}^- \rightarrow \text{HgCl}_2$ $\text{For Thallium(I) sulphate:}$ $\text{Thallium(I) means Tl}^+ \text{ (oxidation state +1)}$ $\text{Sulphate is SO}_4^{2-} \text{ (charge -2)}$ $\text{To balance charges: } 2\text{Tl}^+ + \text{SO}_4^{2-} \rightarrow \text{Tl}_2\text{SO}_4$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}