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Current Question (ID: 8571)

Question:
$\text{The oxidation number and covalency of sulphur in the sulphur molecule (S}_8\text{) are respectively:}$
Options:
  • 1. $0, \text{ and } 2$
  • 2. $+6, \text{ and } 8$
  • 3. $0, \text{ and } 8$
  • 4. $+6, \text{ and } 2$
Solution:
$\text{HINT: Covalency is defined for elements that form covalent bonds whereas valency is used for covalent and ionic bonds.}$ $\text{Oxidation number in elemental form is zero. Co-valency is two because of S-S-S-S-chain.}$ $\text{Explanation:}$ $\text{1. Oxidation number: In the elemental form S}_8\text{, sulfur has an oxidation number of 0 because it is in its elemental state.}$ $\text{2. Covalency: Each sulfur atom in the S}_8 \text{ ring structure forms exactly 2 covalent bonds with adjacent sulfur atoms, creating a continuous S-S-S-S chain.}$ $\text{Therefore, the oxidation number is 0 and the covalency is 2.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}