Import Question JSON

\text{Hint: Intramolecular redox change involve oxidation of one atom and reduction of another atom within a molecule.} \\ \text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2\text{H}_2\text{O} \\ \text{(-3)} \quad \text{(+3)} \quad \text{(0)} \\ \text{oxidation} \quad \text{reduction} \\ \text{Mn}_2\text{O}_7 \rightarrow \text{MnO}_2 + 3\text{O}_2 \\ \text{(+7)} \quad \text{(-2)} \quad \text{(+4)} \quad \text{(0)} \\ \text{reduction} \quad \text{oxidation} \\ \text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2 \\ \text{(+5)} \quad \text{(-2)} \quad \text{(-1)} \quad \text{(0)} \\ \text{reduction} \quad \text{oxidation} \\ \text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \\ \text{(-1)} \quad \text{(-2)} \quad \text{(0)} \\ \text{reduction} \quad \text{oxidation} \\ \text{In 1st case its one N, with +3 state undergoes reduction, where as another nitrogen with -3 undergoes oxidation, its not a disproportionation reaction because in that case reactant atom must have one oxidation state.} \\ \text{In 2nd case, its Mn which undergoes reduction and O which undergoes oxidation.} \\ \text{In 3rd case - its Cl which undergoes reduction and O undergoes oxidation.} \\ \text{Where as in 4th case, its O of H}_2\text{O}_2 \text{ which undergoes oxidation as well as reduction, so it will be a disproportionation reaction}