Import Question JSON

Current Question (ID: 8586)

Question:

$ \text{Which of the following arrangements represents the increasing oxidation number of the central atom?} $

Options:

1. $ \text{CrO}_2^-, \text{ClO}_3^-, \text{CrO}_4^{2-}, \text{MnO}_4^- $
2. $ \text{ClO}_3^-, \text{CrO}_4^{2-}, \text{MnO}_4^-, \text{CrO}_2^- $
3. $ \text{CrO}_2^-, \text{ClO}_3^-, \text{MnO}_4^-, \text{CrO}_4^{2-} $
4. $ \text{CrO}_4^{2-}, \text{MnO}_4^-, \text{CrO}_2^-, \text{ClO}_3^- $

Solution:

\text{Hint: The oxidation number of oxygen atom is -2.} \text{Writing the oxidation number (O.N.) of Cr, Cl and Mn on each species in the four set ions, then,} \text{(1) } \overset{+3}{\text{Cr}}\text{O}_2^-, \overset{+5}{\text{Cl}}\text{O}_3^-, \overset{+6}{\text{Cr}}\text{O}_4^{2-}, \overset{+7}{\text{Mn}}\text{O}_4^- \text{(2) } \overset{+5}{\text{Cl}}\text{O}_3^-, \overset{+6}{\text{Cr}}\text{O}_4^{2-}, \overset{+7}{\text{Mn}}\text{O}_4^-, \overset{+3}{\text{Cr}}\text{O}_2^- \text{(3) } \overset{+3}{\text{Cr}}\text{O}_2^-, \overset{+5}{\text{Cl}}\text{O}_3^-, \overset{+7}{\text{Mn}}\text{O}_4^-, \overset{+6}{\text{Cr}}\text{O}_4^{2-} \text{(4) } \overset{+6}{\text{Cr}}\text{O}_4^{2-}, \overset{+7}{\text{Mn}}\text{O}_4^-, \overset{+3}{\text{Cr}}\text{O}_2^-, \overset{+5}{\text{Cl}}\text{O}_3^- \text{Only in the arrangement (1), the oxidation number of central atom increases from left to right, therefore, option (1) is correct.}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}