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Current Question (ID: 8589)

Question:

$\text{The oxidation states of P in } \text{H}_4\text{P}_2\text{O}_5, \text{H}_4\text{P}_2\text{O}_6, \text{H}_4\text{P}_2\text{O}_7, \text{ are respectively -}$

Options:

1. $+3, +5, +4$
2. $+5, +3, +4$
3. $+5, +4, +3$
4. $+3, +4, +5$

Solution:

$\text{Key Idea: Oxidation state of H is +1 and that of O is -2.}$ $\text{Let the oxidation state of P in the given compounds is x.}$ $\text{In } \text{H}_4\text{P}_2\text{O}_5:$ $(+1) \times 4 + 2 \times x + (-2) \times 5 = 0$ $4 + 2x - 10 = 0$ $2x = 6$ $x = +3$ $\text{In } \text{H}_4\text{P}_2\text{O}_6:$ $(+1) \times 4 + 2x + (-2) \times 6 = 0$ $4 + 2x - 12 = 0$ $2x = 8$ $x = +4$ $\text{In } \text{H}_4\text{P}_2\text{O}_7:$ $(+1) \times 4 + 2 \times x + (-2) \times 7 = 0$ $4 + 2x - 14 = 0$ $2x = 10$ $x = +5$ $\text{Thus, the oxidation states of P in } \text{H}_4\text{P}_2\text{O}_5, \text{H}_4\text{P}_2\text{O}_6, \text{H}_4\text{P}_2\text{O}_7 \text{ are } +3, +4 \text{ and } +5 \text{ respectively.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}