Import Question JSON

Current Question (ID: 8590)

Question:

\text{The correct statement(s) about the given reaction is -} \text{XeO}_6^{4-}\text{(aq)} + 2\text{F}^-\text{(aq)} + 6\text{H}^+\text{(aq)} \rightarrow \text{XeO}_3\text{(g)} + \text{F}_2\text{(g)} + 3\text{H}_2\text{O}\text{(l)}

Options:

1. $ \text{XeO}_6^{4-} \text{ oxidises F}^- $
2. $ \text{The oxidation number of F increases from -1 to zero} $
3. $ \text{XeO}_6^{4-} \text{ is a stronger oxidizing agent than F}^- $
4. $ \text{All of the above.} $

Solution:

\text{The given reaction occurs because } \text{XeO}_6^{4-} \text{ oxidises } \text{F}^- \text{ and } \text{F}^- \text{ reduces } \text{XeO}_6^{4-}\text{.} \text{Xe}^{+8}\text{O}_6^{4-} \text{(aq)} + 2\text{F}^{-1-} \text{(aq)} + 6\text{H}^+ \text{(aq)} \rightarrow \text{Xe}^{+6}\text{O}_3 \text{(g)} + \text{F}_2^0 \text{(g)} + 3\text{H}_2\text{O} \text{(l)} \text{In this reaction, the oxidation number (O.N.) of Xe decreases from +8 in } \text{XeO}_6^{4-} \text{ to +6 in } \text{XeO}_3 \text{ and the O.N. of F increases from -1 in } \text{F}^- \text{ to 0 in } \text{F}_2\text{.} \text{Hence, we can conclude that } \text{XeO}_6^{4-} \text{ is a stronger oxidizing agent than } \text{F}^-\text{.}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}