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Current Question (ID: 8594)

Question:
$\text{What is the alteration in the oxidation state of carbon in the given reaction?}$ $\text{CH}_{4(g)} + 4\text{Cl}_{2(g)} \rightarrow \text{CCl}_{4(l)} + 4\text{HCl}_{(g)}$
Options:
  • 1. $0 \text{ to } +4$
  • 2. $-4 \text{ to } +4$
  • 3. $0 \text{ to } -4$
  • 4. $+4 \text{ to } +4$
Solution:
$\text{To find the alteration in the oxidation state of carbon, we need to calculate its oxidation state in the reactant } \text{CH}_4 \text{ and the product } \text{CCl}_4\text{.}$ $\text{Step 1: Oxidation state of Carbon in } \text{CH}_4 \text{ (Methane)}$ $\text{In } \text{CH}_4\text{, hydrogen (H) usually has an oxidation state of } +1\text{.}$ $\text{Let the oxidation state of Carbon (C) be } x\text{.}$ $x + 4 \times (+1) = 0 \text{ (since } \text{CH}_4 \text{ is a neutral molecule)}$ $x + 4 = 0$ $x = -4$ $\text{So, the oxidation state of carbon in } \text{CH}_4 \text{ is } -4\text{.}$ $\text{Step 2: Oxidation state of Carbon in } \text{CCl}_4 \text{ (Carbon Tetrachloride)}$ $\text{In } \text{CCl}_4\text{, chlorine (Cl) usually has an oxidation state of } -1 \text{ (as it is more electronegative than carbon in this compound).}$ $\text{Let the oxidation state of Carbon (C) be } y\text{.}$ $y + 4 \times (-1) = 0 \text{ (since } \text{CCl}_4 \text{ is a neutral molecule)}$ $y - 4 = 0$ $y = +4$ $\text{So, the oxidation state of carbon in } \text{CCl}_4 \text{ is } +4\text{.}$ $\text{The alteration in the oxidation state of carbon is from } -4 \text{ to } +4\text{.}$ $\text{Additionally, let's look at the other elements for completeness:}$ $\text{Chlorine (Cl):}$ $\text{In } \text{Cl}_2\text{, the oxidation state of Cl is } 0 \text{ (elemental form).}$ $\text{In } \text{HCl}\text{, hydrogen is } +1 \text{, so chlorine is } -1\text{.}$ $\text{Chlorine is reduced from } 0 \text{ to } -1\text{.}$ $\text{Since carbon's oxidation state increases from } -4 \text{ to } +4\text{, carbon undergoes oxidation.}$ $\text{Therefore, the alteration in the oxidation state of carbon is } -4 \text{ to } +4\text{.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}