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Current Question (ID: 8604)

Question:
$\text{Sn}^{++} \text{ loses two electrons in a reaction. The final oxidation number of tin will be:}$
Options:
  • 1. $+2$
  • 2. $\text{Zero}$
  • 3. $+4$
  • 4. $-2$
Solution:
$\text{Hint: Loss of electrons is known as oxidation.}$ $\text{The initial oxidation number of tin is represented by } \text{Sn}^{++} \text{, which means it has a charge of } +2 \text{. Therefore, its initial oxidation number is } +2\text{.}$ $\text{When an atom or ion loses electrons, its positive charge increases or its negative charge decreases.}$ $\text{In this case, } \text{Sn}^{2+} \text{ loses two electrons.}$ $\text{The reaction can be written as:}$ $\text{Sn}^{2+} \rightarrow \text{Sn}^{(2+2)+} + 2\text{e}^{-}$ $\text{Sn}^{2+} \rightarrow \text{Sn}^{4+} + 2\text{e}^{-}$ $\text{Losing 2 electrons will add 2 more positive charges to } \text{Sn}^{2+}\text{.}$ $\text{Initial charge} = +2$ $\text{Change in charge} = +2 \text{ (due to loss of 2 electrons)}$ $\text{Final charge} = \text{Initial charge} + \text{Change in charge}$ $\text{Final charge} = +2 + (+2) = +4$ $\text{Therefore, the final oxidation number of tin will be } +4\text{.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}