Import Question JSON

Current Question (ID: 8617)

Question:

$\text{Given below are two statements:}$ $\text{Assertion (A): The decomposition of hydrogen peroxide to form water and oxygen is an example of a disproportionation reaction.}$ $\text{Reason (R): The oxygen of peroxide is in -1 oxidation state and it is converted to zero oxidation state in O}_2 \text{ and -2 oxidation state in H}_2\text{O.}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{(A) is False but (R) is True.}$

Solution:

$\text{Hint: Disproportionation reaction is a redox}$ $\text{Disproportionation is a redox reaction in which one compound of intermediate oxidation state converts to two compounds, one of higher and one of lower oxidation states.}$ $\text{The reaction is as follows:}$ $2\text{H}_2\text{O}_2\text{(aq)} \rightarrow 2\text{H}_2\text{O}\text{(l)} + \text{O}_2\text{(g)}$ $\text{Here the oxygen of peroxide, which is present in -1 state, is converted to zero oxidation state in O}_2 \text{ undergoing oxidation and decreases to -2 oxidation state in H}_2\text{O undergoing reduction. So, it is an example of disproportionation reaction.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}