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Current Question (ID: 8620)

Question:
$\text{The set of metals that can show disproportionation reaction is:}$
Options:
  • 1. $\text{Cu, Na, Li}$
  • 2. $\text{Mg, F, Ne}$
  • 3. $\text{P, Cl, S}$
  • 4. $\text{Mn, Cu, Ga}$
Solution:
$\text{Hint: In a disproportionation reaction, the same element is simultaneously oxidized and reduced.}$ $\text{In disproportionation reactions, one of the reacting substances always contains an element that can exist in at least three oxidation states.}$ $\text{(a) P, Cl, and S are nonmetals that can show disproportionation reactions as these elements can exist in three or more oxidation states.}$ $\text{(b) Mn, Cu, and Ga are metals that show disproportionation reactions as these elements can exist in three or more oxidation states.}$ $\text{The reactions are as follows:}$ $2\text{Mn}^{3+} \rightarrow \text{Mn}^{2+} + \text{MnO}_2$ $2\text{Cu}^{+} \rightarrow \text{Cu}^{2+} + \text{Cu}$ $3\text{GaX} \rightarrow 2\text{Ga} + 3\text{X}^{-} + \text{Ga}^{3+}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}