Import Question JSON

Current Question (ID: 8625)

Question:

$\text{The correct statement about the given reaction is-}$ $(\text{CN})_2\text{(g)} + 2\text{OH}^-\text{(aq)} \rightarrow \text{CN}^-\text{(aq)} + \text{CNO}^-\text{(aq)} + \text{H}_2\text{O}\text{(l)}$

Options:

1. $\text{The reaction is an example of a disproportionation reaction.}$ (Correct)
2. $\text{Hydrogen atom gets oxidized.}$
3. $\text{Reaction occurs in acidic medium.}$
4. $\text{None of the above}$

Solution:

$\text{Hint: Disproportionation Reaction}$ $\text{The oxidation numbers of carbon in } (\text{CN})_2, \text{CN}^- \text{ and CNO}^- \text{ are +3, +2, and +4 respectively.}$ $\text{The oxidation number of carbon in the various species is:}$ $\left(\overset{+3}{\text{CN}}\right)_2\text{(g)} + 2\text{OH}^-\text{(aq)} \rightarrow \overset{+2}{\text{CN}}^-\text{(aq)} + \overset{+4}{\text{CNO}}^-\text{(aq)} + \text{H}_2\text{O}\text{(l)}$ $\text{It can be easily observed that the same compound is being reduced and oxidized simultaneously in the given equation. Reactions in which the same compound is reduced and oxidized are known as disproportionation reactions.}$ $\text{Thus, it can be said that the alkaline decomposition of cyanogen is an example of a disproportionation reaction.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}