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Current Question (ID: 8626)

Question:

$\text{The standard electrode potential (E}^\circ\text{) values of Al}^{3+}\text{/ Al, Ag}^+\text{ / Ag, K}^+\text{ / K, and Cr}^{3+}\text{ / Cr are -1.66 V, 0.80 V, -2.93 V \& -0.79 V respectively. The correct decreasing order of the reducing power of the metal is:}$

Options:

1. $\text{Ag} > \text{Cr} > \text{Al} > \text{K}$
2. $\text{K} > \text{Al} > \text{Cr} > \text{Ag}$
3. $\text{K} > \text{Al} > \text{Ag} > \text{Cr}$
4. $\text{Al} > \text{K} > \text{Ag} > \text{Cr}$

Solution:

$\text{Hint: Reducing power of a substance is directly proportional to its standard oxidation potential value.}$ $\text{Explanation:}$ $\text{A higher tendency to lose electrons will show higher reducing power. Secondly, as the standard reduction electrode potential value increases the tendency of reducing power decreases.}$ $\text{The order of given standard electrode potential is as follows:}$ $\text{Ag}^+\text{ / Ag} > \text{Cr}^{3+}\text{ / Cr} > \text{Al}^{3+}\text{ / Al} > \text{K}^+\text{/K}$ $\text{The reducing power of a substance is as follows:}$ $\text{K}>\text{Al}>\text{Cr}>\text{Ag}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}