Import Question JSON

Current Question (ID: 8632)

Question:

$\text{The strongest oxidizing agent is the one which gets reduced most easily (as oxidizing agent itself gets reduced while oxidizing other species) or in other words, has the highest reduction potential.}$ $\text{During reduction,}$ $\text{Oxidized form} + n\text{e}^- \rightarrow \text{Reduced form}$ $\text{Take note that the species which have lower reduction potential are stronger reducing agents while the species which have higher reduction potential are stronger oxidizing agents.}$ $[\text{Fe}(\text{CN})_6]^{3-} + \text{e}^- \rightarrow [\text{Fe}(\text{CN})_6]^{4-} ; \text{E}^\circ = 0.35\text{ V}$ $\text{Fe}^{3+} + \text{e}^- \rightarrow \text{Fe}^{2+} ; \text{E}^\circ = 0.77\text{ V}$ $\text{Here Fe}^{+3} \text{ has the highest reduction potential of 0.77 V. Hence, Fe}^{3+} \text{ is strongest oxidizing agent.}$ $\text{The strongest oxidizing agent in the above equation is:}$

Options:

1. $[\text{Fe}(\text{CN})_6]^{4-}$
2. $\text{Fe}^{2+}$
3. $\text{Fe}^{3+}$
4. $[\text{Fe}(\text{CN})_6]^{3-}$

Solution:

$[\text{Fe}(\text{CN})_6]^{4-} \rightarrow [\text{Fe}(\text{CN})_6]^{3-} + \text{e}^- ; \text{E}^\circ = -0.35\text{ V}$ $\text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + \text{e}^- ; \text{E}^\circ = -0.77\text{ V}$ $\text{Given reduction potentials:}$ $[\text{Fe}(\text{CN})_6]^{3-} + \text{e}^- \rightarrow [\text{Fe}(\text{CN})_6]^{4-} ; \text{E}^\circ = 0.35\text{ V}$ $\text{Fe}^{3+} + \text{e}^- \rightarrow \text{Fe}^{2+} ; \text{E}^\circ = 0.77\text{ V}$ $\text{The strongest oxidizing agent has the highest reduction potential.}$ $\text{Comparing the reduction potentials: Fe}^{3+} \text{ (0.77 V) > [Fe(CN)}_6]^{3-} \text{ (0.35 V)}$ $\text{Therefore, Fe}^{3+} \text{ is the strongest oxidizing agent among the given species.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}