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Current Question (ID: 8636)

Question:

$\text{In the given reaction,}$ $x\text{BrO}_3^- + y\text{Cr}^{+3} + z\text{H}_2\text{O} \rightarrow \text{Br}_2 + \text{CrO}_4^{2-} + \text{H}^+$ $\text{The coefficients x, y, and z are respectively-}$

Options:

1. $6, 10, 11$
2. $6, 10, 20$
3. $6, 8, 22$
4. $6, 10, 22$

Solution:

$\text{Hint: Cr oxidation state is changed from +3 to +6}$ $\text{The reaction is as follows:}$ $\text{BrO}_3^- + y\text{Cr}^{+3} \rightarrow \text{Br}_2 + \text{CrO}_4^{2-}$ $\text{Oxidation states: Br changes from +5 to 0 (reduction), Cr changes from +3 to +6 (oxidation)}$ $\text{Electron transfer: Each BrO}_3^- \text{ gains 5 electrons, each Cr}^{+3} \text{ loses 3 electrons}$ $\text{To balance electrons: 6BrO}_3^- \text{ (gains 30e}^-\text{) and 10Cr}^{+3} \text{ (loses 30e}^-\text{)}$ $6\text{BrO}_3^- + 10\text{Cr}^{+3} \rightarrow 3\text{Br}_2 + 10\text{CrO}_4^{2-}$ $\text{Adding H}_2\text{O and H}^+ \text{ to balance oxygen and hydrogen:}$ $6\text{BrO}_3^- + 10\text{Cr}^{+3} + 22\text{H}_2\text{O} \rightarrow 3\text{Br}_2 + 10\text{CrO}_4^{2-} + 44\text{H}^+$ $\text{Therefore, x = 6, y = 10, z = 22}$ $\text{The correct answer is option 4th.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}