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Current Question (ID: 8649)

Question:

$\text{When substance A reacts with water, it produces a combustible gas B and a}$ $\text{solution of substances 'C' in water. When another substance 'D' reacts with this}$ $\text{solution of C, it produces the same gas 'B' on warming but 'D' can produce gas}$ $\text{'B' on reaction with dilute sulphuric acid at room temperature. 'A' imparts a}$ $\text{deep golden yellow colour to a smokeless flame of a bunsen burner. A, B, C}$ $\text{and D respectively are -}$

Options:

1. $\text{Na, H}_2, \text{NaOH, Zn}$
2. $\text{K, H}_2, \text{KOH, Al}$
3. $\text{Ca, H}_2, \text{Ca}(\text{OH})_2, \text{Sn}$
4. $\text{CaC}_2, \text{C}_2\text{H}_2, \text{Ca}(\text{OH})_2, \text{Fe}$

Solution:

$\text{Hint: Sodium metal produces the deep golden yellow colour flame}$ $\text{Step 1:}$ $\text{Substance A reacts with water, it produces a combustible gas B and a}$ $\text{solution of substances 'C' in water. Hence, A is Na and it will react with water}$ $\text{and produce a combustible gas H}_2\text{ (g) and a solution of substances 'C'}$ $\text{(NaOH) in water. The reaction is as follows:}$ $2\text{Na} + 2\text{H}_2\text{O} \rightarrow \text{H}_2 + 2\text{NaOH}$ $\text{A} \qquad \text{B} \quad \text{C}$ $\text{Step 2:}$ $\text{Substance 'D' reacts with this solution of C, it produces the same gas 'B' on}$ $\text{warming but 'D' can produce gas 'B' on reaction with dilute sulphuric acid at}$ $\text{room temperature. The reaction is as follows:}$ $\text{Zn} + 2\text{NaOH} \rightarrow \text{Na}_2\text{ZnO}_2 + \text{H}_2$ $\text{D} \qquad \text{C} \qquad \text{B}$ $\text{A' imparts a deep golden yellow colour to a smokeless flame of a bunsen}$ $\text{burner. A is sodium metal.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}