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Current Question (ID: 8652)

Question:

$\text{A compound among the following that has hydrogen in the atomic state is -}$

Options:

1. $\text{Metallic hydrides}$
2. $\text{Ionic hydrides}$
3. $\text{Molecular hydrides}$
4. $\text{Water}$

Solution:

$\text{Hint: Hydrogen presents at the interstitial site of another atom.}$ $\text{Explanation:}$ $\text{In metallic hydride or Non-stoichiometric (or Interstitial ) hydrides, hydrogen}$ $\text{atoms have occupied the vacancies in between metal atoms.}$ $\text{Hence, here hydrogen exists in the atomic state. In Ionic hydrides, are}$ $\text{compounds of hydrogen with strongly electropositive metals, i.e. alkali and}$ $\text{alkaline earth metals and some highly positive members of the lanthanide}$ $\text{series with the exception of Be* and Mg* which }\text{c} \sim \text{n}\text{ transfer electrons easily}$ $\text{to hydrogen atoms.}$ $\text{Covalent hydrides are molecular compounds in which hydrogen are}$ $\text{covalently bonded to another element. For example some covalent hydrides}$ $\text{are }\text{NH}_3, \text{H}_2\text{O}, \text{H}_2\text{O}_2\text{ and HF.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}