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Current Question (ID: 8654)

Question:

$\text{Fe} + \text{H}_2\text{O} \xrightarrow{1023-1073\text{K}} \text{Product}$ $\left(\text{Steam}\right)$ $\text{Product formed is -}$

Options:

1. $\text{FeO} + \text{H}_2$
2. $\text{Fe}_2\text{O}_3 + \text{H}_2\text{O}$
3. $\text{Fe}_2\text{O}_3 + \text{H}_2$
4. $\text{Fe}_3\text{O}_4 + \text{H}_2$

Solution:

$\text{HINT: Hydrogen gas is produced.}$ $\text{Explanation:}$ $\text{Step 1:}$ $\text{Iron (Fe) being moderately reactive does not react with ordinary water. The reaction takes place only when the iron is red hot and water is in steam form.}$ $\text{The reaction takes place as a reduction reaction in which Magnetite is formed and hydrogen gas is liberated.}$ $\text{Step 2:}$ $\text{The reaction is as follows:}$ $3\text{Fe} + 4\text{H}_2\text{O}_{(\text{steam})} \xrightarrow{1023-1073\text{K}} \text{Fe}_3\text{O}_4 + 4\text{H}_2 \uparrow$ $\text{Iron reacts with steam to form hydrogen gas and the oxide } \text{Fe}_3\text{O}_4\text{.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}