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Current Question (ID: 8669)

Question:

$\text{The correct order of increasing electrical conductance is -}$

Options:

1. $\text{BeH}_2 > \text{CaH}_2 > \text{TiH}_2$
2. $\text{BeH}_2 < \text{CaH}_2 > \text{TiH}_2$
3. $\text{TiH}_2 < \text{BeH}_2 < \text{CaH}_2$
4. $\text{BeH}_2 < \text{CaH}_2 < \text{TiH}_2$

Solution:

$\text{Hint: Ionic character }\propto \text{ Conductivity}$ $\text{The electrical conductance of a molecule depends upon its ionic or covalent}$ $\text{nature.}$ $\text{Ionic compounds conduct electricity whereas covalent compounds do not.}$ $\text{BeH}_2\text{ is a covalent hydride. Hence, it does not conduct electricity. CaH}_2\text{ is an}$ $\text{ionic hydride, which conducts electricity in the molten state. TiH}_2\text{ is metallic}$ $\text{in nature and conducts electricity at room temperature.}$ $\text{The increasing order of electrical conductance is }\text{BeH}_2 < \text{CaH}_2 < \text{TiH}_2$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}