Import Question JSON

Current Question (ID: 8685)

Question:

$\text{A compound that can remove both temporary and permanent hardness of water is -}$

Options:

1. $\text{NaHCO}_3$
2. $\text{Boiling}$
3. $\text{Ca(OH)}_2$
4. $\text{Na}_6\text{P}_6\text{O}_{18}$

Solution:

$\text{Hint: The complex salt of metaphosphoric acid, sodium hexametaphosphate (NaPO}_3\text{)}_6\text{, is known as Calgon.}$ $\text{Boiling and calcium hydroxide is only used to remove temporary hardness.}$ $\text{The addition of Calgon to hard water causes the calcium and magnesium ions of hard water to displace sodium ions from the anion of Calgon.}$ $\text{This results in the removal of calcium and magnesium ions from hard water in the form of a complex with Calgon. Hence, Calgon is the method used to remove both hardness.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}