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Current Question (ID: 8686)

Question:
$\text{H}_2\text{O}_2 \text{ acts as a -}$
Options:
  • 1. $\text{Bleaching agent}$
  • 2. $\text{Oxidising agent}$
  • 3. $\text{Oxidant for a rocket fuel}$
  • 4. $\text{All of the above}$
Solution:
$\text{Hint: H}_2\text{O}_2 \text{ is an oxidizing agent}$ $\text{Explanation:}$ $\text{H}_2\text{O}_2 \text{ can act both as a reducing agent and oxidizing agent. The oxidation reaction is as follows:}$ $\text{PbS} + 4\text{H}_2\text{O}_2 \rightarrow \text{PbSO}_4 + 4\text{H}_2\text{O} \text{ (oxidation reaction)}$ $\text{Due to its oxidizing nature, H}_2\text{O}_2 \text{ acts as the bleaching agent.}$ $\text{H}_2\text{O}_2 \rightarrow \text{H}_2\text{O} + [\text{O}]$ $\text{Coloured material} + [\text{O}] \rightarrow \text{Colourless material}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}